Asked by Mimi
A gallon starts rising from the ground from rest with an upward acceleration 2m/s^2. Just after 1s, a stone is dropped from it. The time taken by stone to strike the ground is nearly
1) 0.3s
2) 0.7s
3) 1s
4) 1.4s
1) 0.3s
2) 0.7s
3) 1s
4) 1.4s
Answers
Answered by
Scott
i'm guessing a "balloon"?
at t=1s ... the balloon has an upward velocity of 2 m/s
... the height of the balloon is 1 m ... average velocity of 1 m/s for 1 s
the free-fall equation is ... h = 1/2 g t^2 + 2 t + 1
... solve the equation for h = 0 ... stone on the ground
... remember, g is -9.8 m/s^2
at t=1s ... the balloon has an upward velocity of 2 m/s
... the height of the balloon is 1 m ... average velocity of 1 m/s for 1 s
the free-fall equation is ... h = 1/2 g t^2 + 2 t + 1
... solve the equation for h = 0 ... stone on the ground
... remember, g is -9.8 m/s^2
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