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Asked by Anonymous

Solve each system of equations by substitution:
x^2 - y +2 = 0
4x = 14 -y

y + 2x = x^2 - 6
x + y - 3 = 2x^2
7 years ago

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Answered by bobpursley
x^2 - y +2 = 0
4x = 14 -y
y=14-4x

x^2-(14-4x) +2=0
x^2+4x-12=0
(x+6)(x-2)=0
x=6; x=2, y=-10;6
7 years ago
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Question

Solve each system of equations by substitution:
x^2 - y +2 = 0
4x = 14 -y

y + 2x = x^2 - 6
x + y - 3 = 2x^2

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