Asked by Anonymous
Solve each system of equations by substitution:
x^2 - y +2 = 0
4x = 14 -y
y + 2x = x^2 - 6
x + y - 3 = 2x^2
x^2 - y +2 = 0
4x = 14 -y
y + 2x = x^2 - 6
x + y - 3 = 2x^2
Answers
Answered by
bobpursley
x^2 - y +2 = 0
4x = 14 -y
y=14-4x
x^2-(14-4x) +2=0
x^2+4x-12=0
(x+6)(x-2)=0
x=6; x=2, y=-10;6
4x = 14 -y
y=14-4x
x^2-(14-4x) +2=0
x^2+4x-12=0
(x+6)(x-2)=0
x=6; x=2, y=-10;6