Asked by Kiff
The equation of a curve is y = 2x^3 + 3x^2
Find:
x-intercept of the curve
y-intercept of the curve
b) Determine the stationery point of the curve.
i) for each point in(b) above, determine whether it is a maximum or a minimum
Find:
x-intercept of the curve
y-intercept of the curve
b) Determine the stationery point of the curve.
i) for each point in(b) above, determine whether it is a maximum or a minimum
Answers
Answered by
bobpursley
y=x^2 (2x+3)
x intercepts: x=0, or x=-1.5
y intercepts (when x=0), y[=0
b. dy/dx=6x^2+6x=0 or x=0 so stationary point is 0,0, and at 1,0
c. d^2/dx^2=12x+6 , at x=0, it is positive, so it is a minimum
at x=-1, it is negative, so a max
x intercepts: x=0, or x=-1.5
y intercepts (when x=0), y[=0
b. dy/dx=6x^2+6x=0 or x=0 so stationary point is 0,0, and at 1,0
c. d^2/dx^2=12x+6 , at x=0, it is positive, so it is a minimum
at x=-1, it is negative, so a max
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.