Asked by Kiff
The gradient of the tangent to curve y = ax^3 + bx at the point (1,1) is -5. Calculate the values of a and b.
dy/dx = 3a^2 + b
-5 =
dy/dx = 3a^2 + b
-5 =
Answers
Answered by
scott
1 = a + b
-5 = 3a + b
solve the system for a and b
-5 = 3a + b
solve the system for a and b
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