Asked by jacqueline
bob accidently falls out of a helicopter that is traveling horizonally at 160m/s. he plunges into the water below 4s later. assuming there is no air resistance, what is the horizontal distance he travels while falling
Answers
Answered by
DrBob222
I would use
distance straight down to the water = 1/2(g)*t^2 which will allow you to determine how high Bob was when he fell out of the plane.
Then distance = rate x time
You know rate and you know time, calculate distance traveled horizontally. Check my thinking.
distance straight down to the water = 1/2(g)*t^2 which will allow you to determine how high Bob was when he fell out of the plane.
Then distance = rate x time
You know rate and you know time, calculate distance traveled horizontally. Check my thinking.
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