Asked by betlehem
a car accidently roll off a cliff. as it leaves the cliff it has a horizontal velocity of 13m/s.it hits the ground 60m from the shoreline. calculate the height of cliff.
Answers
Answered by
Henry
Xo = 13 m/s.
Dx = 60 m.
h = ?
Dx = Xo * Tf = 60
Tf = 60/Xo = 60/13 = 4.62 s. = Fall time.
h = 0.5g*Tf^2 = 4.9*4.62^2 = 105 m.
Dx = 60 m.
h = ?
Dx = Xo * Tf = 60
Tf = 60/Xo = 60/13 = 4.62 s. = Fall time.
h = 0.5g*Tf^2 = 4.9*4.62^2 = 105 m.
Answered by
chali workings
thank you
Answered by
chali workineh
h=1/2 gt^2=105m
Answered by
Tig
What is ^ and *
Answered by
ESRAEL
2x+8x=10
Answered by
Bimiam
What do mean TF
Answered by
eyasu
grade 10 answer acare accidenty off acliff. as it leaves the cliff it has a horizontal velocity of 13m/s, it hits the ground 60 m from the shoreline. calculate the height of the cliff.
Answered by
yirdaw
105m
Answered by
Ephrata Zerfu
105
Answered by
Ephrata Zerfu
how find 0.5
Answered by
Birtukan
To learn
Answered by
Beshenana beyissa
Given required solution X=60m
g=9.8m/s^2 h=? X=Vox.t
Vox=13m/s t=X/vox
t= 60m/13m/s
t=4.62sec
Then now, h=1/2gt^2=0.5*9.8*21.34=104.56m=105m
g=9.8m/s^2 h=? X=Vox.t
Vox=13m/s t=X/vox
t= 60m/13m/s
t=4.62sec
Then now, h=1/2gt^2=0.5*9.8*21.34=104.56m=105m
Answered by
[email protected]
all of d/t person work are nice job
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