Asked by Ayomide
A lamp shade like that of fig 15.26 has a height of 12 cm and upper and lower diameters of 10 cm and 20 cm
A.what area material is required to cover the curve surface of the frustum
B.what is the volume of the frustum?
( Give both answers in terms of pie)
A.what area material is required to cover the curve surface of the frustum
B.what is the volume of the frustum?
( Give both answers in terms of pie)
Answers
Answered by
bobpursley
http://cdn-6.analyzemath.com/Geometry_calculators/frustrum_1.gif
Answered by
Abiodun
(a) 195πcm (b) 700πcm
Answered by
Anonymous
How do you get it
Answered by
Anonymous
How do you get it
Answered by
Anonymous
How did you get it
Answered by
Samuel
A) with lettering by similar triangles= x/5=12/5.
Cross multiply
x=12.
Pythagoream theorem equation: where s is slant height.
s^2=(R-r)^2+h^2
s^2=(10-5)^2 + 12^2
s^2=5^2+12^2
s^2=25+144
s^2=169
Squareroot bothside
s=13.
Surface area of frustum=
Pie*10*26-pie*5*13
=Pie260 - pie65
=pie(260-65)
=pie195 cm^2.
B) volume=1/3*pie*h(R^2+R*r+r^2)
1/3 pie 12(10^2+10*5+5^2)
1/3 * pie *12*175
2100pie/3
=700piecm^3
Cross multiply
x=12.
Pythagoream theorem equation: where s is slant height.
s^2=(R-r)^2+h^2
s^2=(10-5)^2 + 12^2
s^2=5^2+12^2
s^2=25+144
s^2=169
Squareroot bothside
s=13.
Surface area of frustum=
Pie*10*26-pie*5*13
=Pie260 - pie65
=pie(260-65)
=pie195 cm^2.
B) volume=1/3*pie*h(R^2+R*r+r^2)
1/3 pie 12(10^2+10*5+5^2)
1/3 * pie *12*175
2100pie/3
=700piecm^3
Answered by
Queen Priscilla SS1SC
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I know God will me.
Answered by
Michael
this is helping
Answered by
Ayomide
I love this i also hope that I can solve like this too
Answered by
Gift
I don't understand
Answered by
Tomiwa
I understand
Answered by
Joshua
I wish I am the one that solve it
Answered by
Adeola Seun
Self explanatory
Answered by
Angelilbae
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Answered by
Khafiana
I understood it, thanks
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