Asked by Wade
How many minutes does it take to produce 10.0L of oxygen gas (at standard conditions)
by electrolyzing neutral water with a current of 1.3 A? What is the corresponding volume
of hydrogen gas produced?
thanks so much
by electrolyzing neutral water with a current of 1.3 A? What is the corresponding volume
of hydrogen gas produced?
thanks so much
Answers
Answered by
DrBob
2H2O ==> 2H2 + O2
10.0 L O2 at STP = 10/22.4 mols = 0.446 mols or 0.446 x 32 = 14,3 grams O2.
96,485 coulombs will produce 32/4 = 8 g O2 so
coulombs needed = 96,485 x (14.3/8) = ?
Coulombs = amperes x seconds = 1.3*seconds. Plug in coulombs and A and solve for seconds. Convert to minutes. Post your work if you get stuck.
10.0 L O2 at STP = 10/22.4 mols = 0.446 mols or 0.446 x 32 = 14,3 grams O2.
96,485 coulombs will produce 32/4 = 8 g O2 so
coulombs needed = 96,485 x (14.3/8) = ?
Coulombs = amperes x seconds = 1.3*seconds. Plug in coulombs and A and solve for seconds. Convert to minutes. Post your work if you get stuck.
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