Asked by Armstrong

Water of mass 120g at 50°c is added to 200g of water at 1 0°c and the mixture is well stirred . calculate the temperature of the mixture .(neglect heat losses to the surrounding)
Answered by bobpursley
sum of heats gained is zero.
heatgainedhotwater+heatgainedbycoolwater=0
120*c*(Tf-50)+200*c*(Tf-10)=0
solve for Tf
Answered by blinky
Thank u
Answered by gene
pls wats the answer
Answered by najib
to learn
Answered by najib
water of mass 120g
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