a researcher tagged 40 giant turtles in 2008. in 2009 she returned and captured 50 turtles, 16 of which were tagged. In 2010, she returned again and captured 30 turtles, 8 of which were tagged.

a. use a proportion to estimate the turtle population for 2009
b. use a proportion to estimate the turtle population for 2010

User Icon for MsPi_3.14159265 MsPi_3.14159265 answered
6 years ago

in 2008 all 40 caught were tagged...

so... in 2009
16tags/50 caught = 40 tags/TOTAL
solving for x you obtain
(50x40) = 16(TOTAL)
2000 = 16(TOTAL) thus divide both sides by 16...
In 2009 there were 125 turtles
Now you try 2010...

User Icon for Pug lover Pug lover answered
6 years ago

thank you i did it!!!!:)))))

User Icon for MsPi_3.14159265 MsPi_3.14159265 answered
6 years ago

Dear Ms Sue... please check my math... as it is late, and I may not truly be thinking straight :)

User Icon for MsPi_3.14159265 MsPi_3.14159265 answered
6 years ago

Excellent : )

User Icon for Ms. Sue Ms. Sue answered
6 years ago

16tags/50 caught = 40 tags/TOTAL

16T = 2000
T = 125

Yep! I got the same answer! :-)

User Icon for MsPi_3.14159265 MsPi_3.14159265 answered
6 years ago

Nighty Night from Canada! I was up early to watch the Royal Wedding :)

User Icon for Ms. Sue Ms. Sue answered
6 years ago

And good night from southeastern Michigan! It was good to see something beautiful and positive today.

User Icon for BlackNike BlackNike answered
5 years ago

In 2009, 16/50 = 32% of the population was tagged, making the population 40/.32 = 125 (P/40 = 50/16)

In 2010, 8/30 = 26.7% of the population was tagged. So, the population is about 150 (P/40 = 30/8)

User Icon for Explain Bot Explain Bot answered
11 months ago

To estimate the turtle population for 2009 and 2010, we can use proportions based on the number of tagged turtles captured in each year.

a. To estimate the turtle population for 2009:
We know that in 2008, the researcher tagged 40 giant turtles. In 2009, she captured 50 turtles, out of which 16 were tagged. We can set up a proportion to estimate the turtle population for 2009.

Let's represent the unknown population size for 2009 with "P":
(tagged turtles in 2009) / (total turtles captured in 2009) = (tagged turtles in 2008) / (total turtles tagged in 2008)

Using the information we have:
16 / 50 = 40 / P

Now let's solve for P:
16P = 50 * 40
16P = 2000
P = 2000 / 16
P = 125

The estimated turtle population for 2009 is 125.

b. To estimate the turtle population for 2010:
We know that in 2010, the researcher captured 30 turtles, out of which 8 were tagged. Again, we can set up a proportion to estimate the turtle population for 2010.

Let's represent the unknown population size for 2010 with "Q":
(tagged turtles in 2010) / (total turtles captured in 2010) = (tagged turtles in 2008) / (total turtles tagged in 2008)

Using the information we have:
8 / 30 = 40 / Q

Now let's solve for Q:
8Q = 30 * 40
8Q = 1200
Q = 1200 / 8
Q = 150

The estimated turtle population for 2010 is 150.