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A researcher tagged 40 giant turtles in 2008. In 2009 , she returned and captured 50 turtles , 16 of which were tagged. In 2010...Asked by FluttershyK22
A researcher tagged 40 giant turtles in 2008. In 2009, she returned and captured 50 turtles, 16 of which were tagged. In 2010, she returned again and captured 30 turtles, 8 of which were tagged.
A. Use a proportion to estimate the turtle population for 2009
B. Use a proportion to estimate the turtle population for 2010.
A. Use a proportion to estimate the turtle population for 2009
B. Use a proportion to estimate the turtle population for 2010.
Answers
Answered by
Ms. Sue
16/50 = 40/x
16x = 2000
x = 125
Do the same for 2010.
16x = 2000
x = 125
Do the same for 2010.
Answered by
FluttershyK22
thank you but I don't get it
Answered by
BlackNike
In 2009, 16/50 = 32% of the population was tagged, making the population 40/.32 = 125 (P/40 = 50/16)
In 2010, 8/30 = 26.7% of the population was tagged. So, the population is about 150 (P/40 = 30/8)
In 2010, 8/30 = 26.7% of the population was tagged. So, the population is about 150 (P/40 = 30/8)