Asked by Anon
A cricket jumps vertically upwards, and remains in the air for 1.6 s. At
what speed did it leave the ground?
what speed did it leave the ground?
Answers
Answered by
Damon
v = Vi - g t
at the top, v = 0 and t = 1.6/2 = 0.8 s
g = 9.81 m/s^2 approximately
so
0 = Vi -9.81(0.8)
Vi = 9.81(0.8) meters/ scond
at the top, v = 0 and t = 1.6/2 = 0.8 s
g = 9.81 m/s^2 approximately
so
0 = Vi -9.81(0.8)
Vi = 9.81(0.8) meters/ scond
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