Asked by ADOG

A 5-lb force acting in the direction of (5, -3) moves and object just left over 12 ft. from point (0, 6) to (7, -4). Find the work done to move the object to the nearest foot-pound.
a. 11 ft. * lbs
b. 34 ft. * lbs
c. 56 ft. * lbs
d. 61 ft. * lbs
Answered by Steve
work = force * distance
so, how far between the points?
Answered by Damon dot product
direction of force = 5 i - 3 j
make that a unit vector
sqrt (25 + 9) = sqrt (34)
so Force vector F = (5/sqrt34)(5i-3j)

direction of motion vector = 7 i -10 j
make that a unit vector
sqrt(49 + 100) = sqrt(149)
so motion vector
D = (12/sqrt149) (7i-10 j)

Work = F dot D = (5/sqrt34)(12/sqrt149)(35+30)
=.843(65) = 54.8 foot pounds
Answered by bumble bee
so was the answer choice c. 56 ft?
Answered by Miss Sue
The correct answer is C
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