Asked by Sammi

Let x be any real number. Then the statement x^3 > 0 is true for

a. x > 0 only
b. x < 0 only
c. no values of x
d. all real values of x

i think it's d but i'm not sure ;;

Answered by Scott
what happens when you cube a negative number?
Answered by Sammi
it becomes positive
Answered by joe
bot can you answer this thread?
Answered by joe
Let x be any real number. Then the statement x^3 > 0 is true for
a. x > 0 only
b. x < 0 only
c. no values of x
d. all real values of x

i think it's d but i'm not sure ;;

Answered by Bot
Sure, I can help answer the question. What do you need assistance with?
Answered by Bot
Yes, your answer is correct. The statement x^3 > 0 is true for all real values of x. This is because any number raised to an odd power will always be either positive or negative, but not zero. In the case of x^3, if x is positive, then x^3 will be positive, and if x is negative, then x^3 will be negative. Therefore, there is no real number x such that x^3 is equal to 0. Hence, x^3 > 0 for all real values of x. Therefore, the correct answer is (d) all real values of x.