Asked by XXX

For what real number k does the product (25 + ki)*(3+2i) equal a real number?
Answered by Steve
(25 + ki)*(3+2i) = 75+3ki+50i-2k
= 75-2k + (3k+50)i

So, you need 3k+50 = 0, since real numbers have zero imaginary part.

Answered by XXX
are you sure? I need the actual answer.
Answered by Steve
well, geez. You cant solve 3k+50 = 0?

k = -50/3

(25 - 50/3 i)*(3+2i) = 325/3

which is a real number
Answered by Lelface
Uhh 325/3 isn't right
Answered by Anonymous2.0
Um, Lelface the answer isnt 325/3. It's -50/3, like steve said earlier. He was just substituting the answer in to show it worked.
Answered by jimkey17
it's -50/3
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