Correction:
Zn(s) + NO3^-(aq) ---------> ZN^2+(aq) + NO(g)
5.00 g of (Zn) was added to 0.800 moles of nitrate ion in acidic media.
Calculate the volume of (NO) gas collected at STP.
Zn(s) + No3^-(aq) ---------> ZN^2+(aq) + NO(g)
(Must balance the reaction first).
Thank you.
2 answers
3Zn(s) + 2NO3^-(aq) + 8H^+ ---------> 3Zn^2+(aq) + 2NO(g) + 4H2O
This is a limiting reagent (LR) problem. Which is the LR?
mols Zn = grams/atomic mass = approx 0.08
Convert mols Zn to mols NO. That's approx 0.08 x (2 mols NO/3 mols Zn) = about 0.05 which is less than 0.8 mols from the NO3^-.
Then use PV = nRT and solve for V in liters.
This is a limiting reagent (LR) problem. Which is the LR?
mols Zn = grams/atomic mass = approx 0.08
Convert mols Zn to mols NO. That's approx 0.08 x (2 mols NO/3 mols Zn) = about 0.05 which is less than 0.8 mols from the NO3^-.
Then use PV = nRT and solve for V in liters.
4 answers