3. If 5.20 g of HCl is added to enough distilled water to form 3.00 L of solution, what is the molarity of the solution? [Use molecular weight: HCl, 36.46 amu]

Question

3.	If 5.20 g of HCl is added to enough distilled water to form 3.00 L of solution, what is the molarity of the solution? [Use molecular weight: HCl, 36.46 amu]
5.20/36.46= 0.1426 X 3.00=0.428 M
IS THIS CORRECT

DrBob222 · Answer

part right; part wrong; overall is wrong. Yes, mols = grams/molar mass = 0.1426 Then M = mols/L = 0.1426/3.00 L = ? Then round to 3 significant figures.