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g is increasing when g' > 0

g'(x) = f(x)
f(x) > 0 when -3 < x < 6

g(x) = ∫[-2,x] 3 dt = 3t [-2,x] = -6-3x for -3<=x<0
g(x) = ∫[-2,x] 3-t dt = 3t - t^2/2 [-2,x] = x^2/2 - 3x - 8 for 0<=x<=6
g(x) = ∫[-2,x] -3 dt = -3t [-2,x] = 6-3x for 6<x<=9

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