Asked by Kim
Can anyone help me on these two problems also. I am getting so confused and tired.
The length of a rectangle is fixed at 27cm. What lengths will make the perimeter greater than 100cm?
also this problem
Trians A and B are traveling in the same direction on parellel tracks. Trian A is traveling at 40 miles per hour and train B is traveling at 50 miles per hour. Train A passes a station at 7:15am. If train B passes the same station at 7:45am, at what time will train B catch up to train A?
When will train B catch up with train A?
The length of a rectangle is fixed at 27cm. What lengths will make the perimeter greater than 100cm?
also this problem
Trians A and B are traveling in the same direction on parellel tracks. Trian A is traveling at 40 miles per hour and train B is traveling at 50 miles per hour. Train A passes a station at 7:15am. If train B passes the same station at 7:45am, at what time will train B catch up to train A?
When will train B catch up with train A?
Answers
Answered by
bobpursley
The first: doesn't make sense. I will assume you are looking for widths.
P=2Length +2width
100<=2(27)+2*W
solve for w.
P=2Length +2width
100<=2(27)+2*W
solve for w.
Answered by
Kim
Thank you for your help, it is width.
So i take the 2and times it by the 27.
With that answer figure out the difference between the 2 times 27 and minus from 100 then divid by 2. Is this the way to figure out the problem?
So i take the 2and times it by the 27.
With that answer figure out the difference between the 2 times 27 and minus from 100 then divid by 2. Is this the way to figure out the problem?
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