Asked by Anonymous
A particle moves along a curve so that its position at time t is given by the position vector <4e^(3t - 3), cos(t - 1)>. What is the particle's speed at time t = 1?
I think it is 12.
I think it is 12.
Answers
Answered by
Damon
dx/dt =12 (e^3t-3)
dy/dt = -sin(t-1)
at t = 1
dx/dt = 12
dy/dt = 0
so yes 12
dy/dt = -sin(t-1)
at t = 1
dx/dt = 12
dy/dt = 0
so yes 12
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