Asked by Gloria
a particle moves along the x-axis so that its velocity is proportional to x^2. Prove that its acceleration is proportional to x^3
Answers
Answered by
Steve
v = kx^2
a = 2kx
I think you mean that the position may be proportional to x^3
s = k/3 k^3 + c
If c=0, then s = kx^3
a = 2kx
I think you mean that the position may be proportional to x^3
s = k/3 k^3 + c
If c=0, then s = kx^3
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