Asked by Carly
This was a question asked yesterday that I am stuck on also -- could you explain how to solve this using this "log" on the calculator please?
I'm working on a problem where I was given a table and had to find the exponential equation of best fit. The table is about the number of views of videos. The equation is y = 12.0143(1.7498)^x
I had to estimate the number of views after 2 weeks and that is 30,307 views.
The question then was, when will the video reach one million views. I'm not sure how to solve that? Do I make the y 1,000,000, so 1,000,000 = 12.0143(1.7498)^x?
If so, how do I solve that? If not, how to solve?
Thank you.
Steve yesterday at 12:13pm
You are correct
12.0143(1.7498)^x=1000000
(1.7498)^x=83234
x log 1.7498 = log 83234
x = log83234/log1.7498 = 20.25 days
I'm working on a problem where I was given a table and had to find the exponential equation of best fit. The table is about the number of views of videos. The equation is y = 12.0143(1.7498)^x
I had to estimate the number of views after 2 weeks and that is 30,307 views.
The question then was, when will the video reach one million views. I'm not sure how to solve that? Do I make the y 1,000,000, so 1,000,000 = 12.0143(1.7498)^x?
If so, how do I solve that? If not, how to solve?
Thank you.
Steve yesterday at 12:13pm
You are correct
12.0143(1.7498)^x=1000000
(1.7498)^x=83234
x log 1.7498 = log 83234
x = log83234/log1.7498 = 20.25 days
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