Asked by Anonymous
Suppose you have a simple circuit that includes a resistance device of 50 ohms, and the current flowing through it is 2.0 amps. Solve for the potential difference of the batteries.
1.0 E2 V
25 V
0.040 V
2.0 E2 V
1.0 E2 V
25 V
0.040 V
2.0 E2 V
Answers
Answered by
Steve
E=IR=2*50
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