Asked by girly girl
What is a simplified form of the expression [sec^2x-1]/[(sinx)(secx)]?
a. cot x
b. csc x
c. tan x*****
d. sec x tan x
I think this is the correct answer, but I do not understand why. Can someone please explain?
a. cot x
b. csc x
c. tan x*****
d. sec x tan x
I think this is the correct answer, but I do not understand why. Can someone please explain?
Answers
Answered by
Steve
sec^2x-1=tan^2x
So, using that, you have
sin^2x/cos^2x * 1/sinx * cosx = sinx/cosx = tanx
So, using that, you have
sin^2x/cos^2x * 1/sinx * cosx = sinx/cosx = tanx
Answered by
girly girl
Thank you Steve!
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