Asked by Jacqueline

Please help! I don’t know where to start and I need step by step on how to solve:
A gaseous mixture inside a rigid steel vessel contains 75% CO2(g) and 25% H2O (g) by volume at 175 degrees Celcius and 225 kPa. The mixture is then cooled to 0 degrees celcius thereby converting the gaseous water to a liquid. What is the pressure of the CO2 (g) at 0 degrees celcius? Assume that there is no water vapor present after condensation.
Answered by scott
75% of the pressure is CO2 ... 225 kPa * .75

reducing the temperature (absolute) lowers the pressure proportionately

pressure = (225 kPa * .75) * [(0 + 273) / (175 + 273)]
Answered by DrBob222
Note, too, that celsius is the correct spelling.
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