Asked by alex
                if you were to kick a rock on mars at a velocity of 56 feet per second from the top of a 30 foot hill and the equation models h=-1.9^2+56t+30 where h is height and t is time.
How high will the rock get of the surface?
            
        How high will the rock get of the surface?
Answers
                    Answered by
            scott
            
    the max height is on the axis of symmetry of the parabola
tmax = -b / 2a = -56 / (2 * -1.9)
solve for the time at max
... plug the time into the height equation to find max height
    
tmax = -b / 2a = -56 / (2 * -1.9)
solve for the time at max
... plug the time into the height equation to find max height
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