Asked by alex

if you were to kick a rock on mars at a velocity of 56 feet per second from the top of a 30 foot hill and the equation models h=-1.9^2+56t+30 where h is height and t is time.
How high will the rock get of the surface?

Answers

Answered by scott
the max height is on the axis of symmetry of the parabola

tmax = -b / 2a = -56 / (2 * -1.9)

solve for the time at max
... plug the time into the height equation to find max height
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