Asked by Scott

If a gas effuses 1.618 times faster than Kr (molar mass = 83.8 g/mol) what is the molar
mass of the gas?

7 years ago

Answered by bobpursley

1.618/1=sqrt( 83.8/molmassX)
square both sides.
molmassX=83.8/1.618^2
x=32

7 years ago

Answered by Scott

Thank you

7 years ago

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