Question
If a gas effuses 1.618 times faster than Kr (molar mass = 83.8 g/mol) what is the molar
mass of the gas?
mass of the gas?
Answers
bobpursley
1.618/1=sqrt( 83.8/molmassX)
square both sides.
molmassX=83.8/1.618^2
x=32
square both sides.
molmassX=83.8/1.618^2
x=32
Scott
Thank you