Asked by nikki
A sample of neon effuses from a container in 73 seconds. The same amount of an unknown noble gas requires 149 seconds.
Identify the gas.
Identify the gas.
Answers
Answered by
bobpursley
Use Graham's law of effusion.
rateX/rateNe= sqrt (molmassNe/molmassx)
solve for mole mass of x.
Now notice this: rate above is volume/time
You are given time. So if you want to plug in the given times, the equation becomes
time1/timeNe=sqrt(molmass1/timeNe)
rateX/rateNe= sqrt (molmassNe/molmassx)
solve for mole mass of x.
Now notice this: rate above is volume/time
You are given time. So if you want to plug in the given times, the equation becomes
time1/timeNe=sqrt(molmass1/timeNe)
Answered by
nikki
i am not doing it right , first i got Hydrogen and then Helium...im not sure what im doing wrong
Answered by
bobpursley
149/73= sqrt(molmassX/20.18)
molmassX=4.16*20.18
The closest Nobel element is Radon.
molmassX=4.16*20.18
The closest Nobel element is Radon.
Answered by
Ben
The closest would be Krypton, not Radon
Answered by
cat
wouldnt the equation be 149/73=sqrt(20.18/molar massx)
Answered by
Kris
No it is inverse
Answered by
Morgan
How did you get the 4.16?
Answered by
Matt
149 Ne/73 unknown = sqrt(MM unknown/20.183)
Square root the denominator
2.0411 = sqrt(MM unknown)/ 4.4925
multiply the denominator to isolate the unknown
2.0411 x 4.4925 = sqrt(MM unknown)
9.16972 = sqrt(MM)
Square both sides,
84.083 = unknown molar mass, closest element is the noble gas Radon.
Square root the denominator
2.0411 = sqrt(MM unknown)/ 4.4925
multiply the denominator to isolate the unknown
2.0411 x 4.4925 = sqrt(MM unknown)
9.16972 = sqrt(MM)
Square both sides,
84.083 = unknown molar mass, closest element is the noble gas Radon.
Answered by
Matt
Bleh, I meant Krypton, not Radon.
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