Asked by A.S

The largest stable nucleus has a nucleon number of 209, and the smallest has a nucleon number of 1. If each nucleus is assumed to be a sphere, what is the ratio (largest/smallest) of the surface areas of these spheres? (Area209/Area1)

Please help!! I have a quiz due!!

Thanks
Answered by scott
sphere volume ... 4/3 π r^3

surface area ... 4 π r^2

s.a. = k v^(2/3)

Area209 / Area1 = k[209^(2/3)] / k[1^(2/3)] = 209^(2/3)
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