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A spring with a force constant of 111 Nm is attached to the ceiling. When an unknown mass is attached it pulls the spring down...Asked by Alicia
spring with a force constant of 111 Nm is attached to the ceiling. When an unknown mass is attached it pulls the spring down 0.340m to its equilibrium position. The mass is then pulled 9cm below its equilibrium position and oscillations back and forth. Determine the period of oscillation(in seconds)?
Answers
Answered by
bobpursley
mg=111*.340
m= 111*.340/9.8 kg
Period= 2PI*sqrt(m/k)= 2*pi*sqrt(111*.34/(9.8*111))=2PIsqrt(.34/9.8)
m= 111*.340/9.8 kg
Period= 2PI*sqrt(m/k)= 2*pi*sqrt(111*.34/(9.8*111))=2PIsqrt(.34/9.8)
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