Asked by k

An Artisan has 63 kg of metal of density 7,000kg/m3. He intends to use make a rectangular pipe with external dimensions 12 cm by 15 cm and internal dimensions 10 cm by 12 cm. Calculate the length of the pipe in meters.
Answered by Steve
the cross-section of the pipe is a rectangular ring with area
A = (12*15)-(10*12) = 60 cm^2
so, if the pipe has length x meters, its volume is (60/100)^2*x = 36x/100 m^3
since mass = density * volume, we have

7000*36x/100 = 63
x = 63/2520 = 1/40 m
Answered by okero Gloria
its allitle bit challemging though
Answered by okero Gloria
its allitle bit challenging though
Answered by Ian fidel
Volume=63kg ÷ 7000kg/m^3
=0.009m^3
Cross section Area = (12×15)-(10×12)=60cm
60cm^2=0.006m^2
0.009m^3÷0.006m^2= 1.5m
Answer =1.5metres
Answered by Peter sumaile
On my side I speculate, the question was supposed to have asked the volume of the material required to make the pipe,
That is you have to find difference in cross-sections multiplied by the height.
Answered by Caleb
Why do we subtract 180 and 120 to find the product of width and height ?