Asked by Jesse
How long, in seconds, would it take to deposit 10.5 g of copper onto an electrode from a solution of Cu2+ if a current of 2.00 A was applied?
Answers
Answered by
DrBob222
Coulombs = amperes x seconds = ? You gave amperes; you need seconds.
You know 63.5/2 grams Cu (approx 32 g) will be deposited with 96,485 coulombs so
96,485 coulombs x (10.5/32) = approx 30000,
Note that my numbers are approx so you need to go through and refine ALL of them
Now you know total coulombs, so plug this number back into the first equation at the top and solve for seconds. Convert to minutes or hours if that is needed.
Post your work if you get stuck.
You know 63.5/2 grams Cu (approx 32 g) will be deposited with 96,485 coulombs so
96,485 coulombs x (10.5/32) = approx 30000,
Note that my numbers are approx so you need to go through and refine ALL of them
Now you know total coulombs, so plug this number back into the first equation at the top and solve for seconds. Convert to minutes or hours if that is needed.
Post your work if you get stuck.
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