Asked by Nick
Need help with Chemistry, thanks in advance!
For the system: 2H2O(g) ↔ 2H2(g) + O2(g) ; at equilibrium 27.0g of H2O, 0.25g of H2 and 16.0g of O2 was found in a 5.0L flask. Calculate the equilibrium constant, Keq.
For the system: 2H2O(g) ↔ 2H2(g) + O2(g) ; at equilibrium 27.0g of H2O, 0.25g of H2 and 16.0g of O2 was found in a 5.0L flask. Calculate the equilibrium constant, Keq.
Answers
Answered by
DrBob222
M H2O - (27.0/18/5) = ?
M H2 = (0.25/2/5) = ?
M O2 = (16.0/32/5) = ?
But note that I don't think those gases will dissolve in that little water.
....................2H2O(g) ↔ 2H2(g) + O2(g)
E........................?..............?..............? from above.
Write the Kc expression and substitute the concns into Kc and calculate.
M H2 = (0.25/2/5) = ?
M O2 = (16.0/32/5) = ?
But note that I don't think those gases will dissolve in that little water.
....................2H2O(g) ↔ 2H2(g) + O2(g)
E........................?..............?..............? from above.
Write the Kc expression and substitute the concns into Kc and calculate.
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