Asked by wayne
You randomly draw marbles from a bag containing both blue and green marbles, without replacing the marbles between draws. If B=drawing a blue marble and G=drawing a green marble, which represents the probability of drawing a blue marble first and a green marble second?
A. P(B)⋅P(G)
B. P(B and G)
C. P(G after B)
D. P(B, then G)
A. P(B)⋅P(G)
B. P(B and G)
C. P(G after B)
D. P(B, then G)
Answers
Answered by
Damon
You are not replacing, so A is hopelessly out
The probability of drawing a green CHANGES after your first draw if you do not replace.
Only one choice is specific about drawing blue first and green second.
The probability of drawing a green CHANGES after your first draw if you do not replace.
Only one choice is specific about drawing blue first and green second.
Answered by
Anonymous
Suppose a bag contains 3 blue and 2 green marbles. You randomly draw 2 marbles without replacement. If B=drawing a blue marble and G=drawing a green marble, which event does NOT have the same probability as the others?
Bag
A. GG
B. BB
C. GB
D. BG
Bag
A. GG
B. BB
C. GB
D. BG
Answered by
nhbvdfxd
yhngrbfeds
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