Asked by Evans
Using the expression of pressure(p) of a gas=1/3pc^-2.where p=density and c^-2=mean square velocity, derive the relation of the kinetic energy of the gas to its temperature
Answers
Answered by
bobpursley
PV=nRT
pressure=1/3 density *meansquarevelocity
1/3 density*meansquarevelociyt*volume=nRT
1/3 mass*meansqurevelociyt=nRT
1/2 mass*meansquarevelocity=3nRT
KE= constant*temperature.
pressure=1/3 density *meansquarevelocity
1/3 density*meansquarevelociyt*volume=nRT
1/3 mass*meansqurevelociyt=nRT
1/2 mass*meansquarevelocity=3nRT
KE= constant*temperature.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.