what would Qc be if the pressure of the container decreased by a factor of 2.417 for the following reaction?
4Hcl(g)+O2(g)<-->2Cl2(g)+2H2O(g)
Kc=13.298 @ 753K
14 years ago
14 years ago
yes, it wants an actual value
11 months ago
To determine the new value of Qc when the pressure of the container decreases by a factor of 2.417, we need to first understand the relationship between Qc and Kc.
Qc represents the reaction quotient, which is calculated the same way as the equilibrium constant Kc but at any given point during the reaction, not just at equilibrium. Qc is calculated by substituting the concentrations (or partial pressures) of the reactants and products into the equilibrium expression.
On the other hand, Kc represents the equilibrium constant and is a measure of the extent to which the reaction proceeds at equilibrium. It is determined at a specific temperature. Kc is calculated using the concentrations (or partial pressures) of the reactants and products at equilibrium.
The equilibrium constant Kc is a constant value for a particular reaction at a specific temperature. It provides insights into the position and extent of the equilibrium. Since Kc is constant, it does not change when the reaction conditions change (such as pressure or volume) unless the temperature is changed.
To calculate the new value of Qc when the pressure of the container decreases by a factor of 2.417, we can use the following relationship:
Qc_new = Qc_old / (pressure factor)^change_in_moles
In this reaction, we can see that there is no change in the number of moles of gas. Therefore, the change_in_moles will be zero, and dividing by zero is undefined.
As a result, we cannot determine a meaningful value for Qc if the pressure of the container decreases by a factor of 2.417 in this specific reaction when there is no change in the number of moles of gas.