Asked by Anonymous
1 supersized cone for $8 or 4 regular-sized cones for $5.
The large cone is has a radius of 5 inches and a height of 12 inches.
Each of the 4 smaller cones have a radius of 2.5 inches and a height of 6 inches.
Which holds more ice cream? the 1 big cone? or the 4 smaller cones combined?
The $8 Large cone volume = 314.159?
The $5 Smaller cone volume = 39.2699?
The volume of the 4 small cones combined = 157.0796
So the larger cone holds more ice cream.
And it should be the better deal right?
The large cone is has a radius of 5 inches and a height of 12 inches.
Each of the 4 smaller cones have a radius of 2.5 inches and a height of 6 inches.
Which holds more ice cream? the 1 big cone? or the 4 smaller cones combined?
The $8 Large cone volume = 314.159?
The $5 Smaller cone volume = 39.2699?
The volume of the 4 small cones combined = 157.0796
So the larger cone holds more ice cream.
And it should be the better deal right?
Answers
Answered by
Reed
Yes, you are coorect
Answered by
bobpursley
Volume of each cone: 1/3 PI*radius^2*height
Volume of supersize: 1/3*PI*25*12=100PI
volume of 4 regulars: 4*1/3*PI*2.5^2*6=50*PI
larger holds more than 4 regular.
better deal:
cost 50 PI icecream: smaller, 5 dollars
cost 50 pi icecream: larger: 8/2=4 dollars
Volume of supersize: 1/3*PI*25*12=100PI
volume of 4 regulars: 4*1/3*PI*2.5^2*6=50*PI
larger holds more than 4 regular.
better deal:
cost 50 PI icecream: smaller, 5 dollars
cost 50 pi icecream: larger: 8/2=4 dollars
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