If α and β are the root of the equation 2X²-7X-3=0 Find α/β+1 + β/α+1

Working answer please

10 answers

x = [ 7 +/- sqrt (49 + 24) ] / 4

α = (7+sqrt 73)/4
β = (7-sqrt 73)/4

now I do not care to go on because I am not sure if you mean what you typed
(α/β)+1
or
α/ (β+1)
It is α/β+1 + β/α+1

That is how the question is
But it is not typed on one line in your book.
What is the numerator and what is the denominator?
You need more parentheses when typing online.
a
---- + 1
b

or

a
------
b+1
α/β + 1 + β/α + 1

Sorry its error in tying
α
---- + 1
β
α/β + 1 + β/α + 1 = α/β + β/α + 2
I still think you may have it wrong
are you sure you do not mean:
α/(β + 1)
+
β/(α + 1 )
Okay .. Please you can still help out with
α/(β + 1)
+
β/(α + 1 )
β+1 = (7-sqrt 73)/4 + 4/4 = (11-sqrt 73)/4
α+1 = (7 +sqrt 73)/4 + 4/4 = (11+sqrt 73)/4

α/(β + 1) = (7+sqrt 73)/(11-sqrt73)
β/(α + 1 ) = (7-sqrt 73)/(11+sqrt 73)

α/(β + 1) = (7+sqrt 73)/(11-sqrt73) * (11+sqrt73)/(11+sqrt73)
β/(α + 1 ) = (7-sqrt 73)/(11+sqrt 73) * (11-sqrt 73)/(11-sqrt 73)

α/(β + 1) = (7+sqrt 73)* (11+sqrt73)/(121-73)
β/(α + 1 ) = (7-sqrt 73) * (11-sqrt 73)/(121- 73)

(77 +18 sqrt 73 +73)/48
(77 - 18 sqrt 73 +73/48
-------------------------------- add
(154 + 146) /48
= 150/48
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