Asked by Patrick

If α and β are the root of the equation 2X²-7X-3=0 Find α/β+1 + β/α+1







Working answer please

Answers

Answered by Anonymous
x = [ 7 +/- sqrt (49 + 24) ] / 4

α = (7+sqrt 73)/4
β = (7-sqrt 73)/4

now I do not care to go on because I am not sure if you mean what you typed
(α/β)+1
or
α/ (β+1)

Answered by Patrick
It is α/β+1 + β/α+1


That is how the question is
Answered by Damon
But it is not typed on one line in your book.
What is the numerator and what is the denominator?
You need more parentheses when typing online.
Answered by Damon
a
---- + 1
b

or

a
------
b+1
Answered by Patrick
α/β + 1 + β/α + 1


Sorry its error in tying
Answered by Patrick
α
---- + 1
β
Answered by Damon
α/β + 1 + β/α + 1 = α/β + β/α + 2
I still think you may have it wrong
are you sure you do not mean:
α/(β + 1)
+
β/(α + 1 )
Answered by Patrick
Okay .. Please you can still help out with
α/(β + 1)
+
β/(α + 1 )
Answered by Damon
β+1 = (7-sqrt 73)/4 + 4/4 = (11-sqrt 73)/4
α+1 = (7 +sqrt 73)/4 + 4/4 = (11+sqrt 73)/4

α/(β + 1) = (7+sqrt 73)/(11-sqrt73)
β/(α + 1 ) = (7-sqrt 73)/(11+sqrt 73)

α/(β + 1) = (7+sqrt 73)/(11-sqrt73) * (11+sqrt73)/(11+sqrt73)
β/(α + 1 ) = (7-sqrt 73)/(11+sqrt 73) * (11-sqrt 73)/(11-sqrt 73)

α/(β + 1) = (7+sqrt 73)* (11+sqrt73)/(121-73)
β/(α + 1 ) = (7-sqrt 73) * (11-sqrt 73)/(121- 73)

(77 +18 sqrt 73 +73)/48
(77 - 18 sqrt 73 +73/48
-------------------------------- add
(154 + 146) /48
= 150/48
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