Question

A bag contains 8 blue coins and 6 red coins. A coin is removed at random and replaced by three of the other color.

a. What is the probability that the removed coin is blue?

b. If the coin removed is blue, what is the probability of drawing a red coin after three red coins are put in the bag to replace the blue one?

c. If the coin removed is red, what is the probability of drawing a red coin after three blue coins are put in the bag to replace the red one?

This one seems a bit confusing

Answer 1

Hello. I believe that the answer to part A is 8/14 is this right?

Answer 2

Yes the answer to part A is 8/14 but that could be simplified more.

Answer 3

Hello Michael I can simplify 8/14=4/7

Is the answer for part b the following:
9/14?

Answer 4

I am confused on part c now though. Can you help with that one please?

Answer 5

for part b, because they took out one and put in 3 more coins, it is now out of 15. so if they put in 3 more coins, there are now 9 red coins. and 15 coins total. what is the probability of pulling out one red coin out of all 15?

Answer 6

on part c they made it so there are 8 red coins and 10 blue coins. In total that is 18. If there are 8 red coins in a bag of 18 coins, what is the probability of pulling out a red coin?

Answer 7

Hello Michael so then my answer would be 9 out of 15.
But if there are 14 coins total and like you said they took out 1 which would be 14 -1=13 plus 3 would that be 16 instead of 15?

Answer 8

Yes sorry! it is out of 16. my mistake! so 9/16 would be the answer for part b.

Answer 9

Hello Michael the probability of pulling out a red coin for part c is 8/18=4/9 is this correct?

Answer 10

Thank you for helping me understand this a lot better I truly appreciate you explaining this to me in more detail so that I could see the big picture Michael. You are very smart and sharp :)

Answer 11

Youre welcome haha and yes thats correct