Asked by kimie

A bag contains 8 blue coins and 6 red coins. A coin is removed at random and replaced by three of the other color.
a) What is the probability that the removed coin is blue?
b) If the coin removed is blue, what is the probability of drawing a red coin after three red coins are put in the bag to replace the blue one?
c) If the coin removed is red, what is the probability of drawing a red coin after three blue coins are put in the bag to replace the red one?
THANK YOU!!!
Answered by Anonymous Cat
A. You would add the number of coins there are (8+6=14) and then find what the question is asking for, which is the probability of removing a blue coin. The answer would be 8/14.

B. You would subtract one blue coin (8-1=7) and add three red ones. (6+3=9) You would find the probability the same way as A. :-)
Answered by katie
The probability of drawing a red coin after three blue coins are put in the bag to replace the red one that has been removed is
Answered by Praise
8+3=11 6-1=5 11+5=16 5/16
Answered by Helper101
All of those people got it wrong!!
A) 4/7
B) 9/16
C) 4/9
Answered by Easy Pete
You are all wrong it is 3/7.
Answered by no one
your all wrong its
10/17
Answered by Bob Olijajebt
ITS 9/16
Answered by 7 grader
9/16
Answered by Yeet
Your all wrong! Becuase the answer changes every time you completely get it wrong!
Answered by LOL
It is

4/7
9/16
5/16
Answered by youdontknowme:D
bro just shut up its a new year and jusst gimme the answer aqlready
Answered by emily
its 4/17 people
Answered by Merilia
3/10