Asked by Patrick
Hello I hope that you are having great evening. I do need a bit of help on the below math problem please.
There are 12 pieces of fruit in a bowl. Seven of the pieces are apples and two are peaches. What is the probability that a randomly selected piece of fruit will not be an apple or a peach. Justify your answer.
How do I do this one?
Thank you
There are 12 pieces of fruit in a bowl. Seven of the pieces are apples and two are peaches. What is the probability that a randomly selected piece of fruit will not be an apple or a peach. Justify your answer.
How do I do this one?
Thank you
Answers
Answered by
Reiny
find the prob(apple or peach) , (similar to the previous question)
the prob NOT apple or peach = 1 - prob(apple or peach)
the prob NOT apple or peach = 1 - prob(apple or peach)
Answered by
Patrick
Hello Reiny,
Well 7 are apples and 2 pieces of fruit are peaches. This basically leaves 3 pieces of fruit that are neither apple or peach. So my answer would be as follows
3/12 = 1/4. you'll have a 25 percent chance because 75 percent is the apples and peaches -Is this correct?
Reiny I am new at this an just learning this a bit so I am not very good at this.
Well 7 are apples and 2 pieces of fruit are peaches. This basically leaves 3 pieces of fruit that are neither apple or peach. So my answer would be as follows
3/12 = 1/4. you'll have a 25 percent chance because 75 percent is the apples and peaches -Is this correct?
Reiny I am new at this an just learning this a bit so I am not very good at this.
Answered by
Reiny
Your are correct, I agree with your answer.
Acceptable answers: 1/4, .25, or 25%
Acceptable answers: 1/4, .25, or 25%
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