Asked by Jillian
Prove the identity.
sin² θ = tan² θ / 1 + tan² θ
sin² θ = tan² θ / 1 + tan² θ
Answers
Answered by
drwls
I assume the right side is supposed to be tan² è /(1 + tan² è)
Start by rewriting
1 + tan^2 = (cos^2 + sin^2)/cos^2
= 1 /cos^2
so that
1/(1+tan^2) = cos^2
Therefore the right side becomes
(sin^2/cos^2)* cos^2 = sin^2
Start by rewriting
1 + tan^2 = (cos^2 + sin^2)/cos^2
= 1 /cos^2
so that
1/(1+tan^2) = cos^2
Therefore the right side becomes
(sin^2/cos^2)* cos^2 = sin^2
Answered by
Jillian
how did 1 + tan^2 become cos^2 + sin ^2?
Answered by
Jillian
oh nevermind i got it thank you.
Answered by
gopi
we know sec^2(x)-tan^2(x)=1
now sec^2(x)=1+tan^2(x)
now tan^2(x)/sec^2(x)=sin^2(x) [tan(x)=sin(x)/cos(x)]
[sec(x)=1/cos(x)]
now sec^2(x)=1+tan^2(x)
now tan^2(x)/sec^2(x)=sin^2(x) [tan(x)=sin(x)/cos(x)]
[sec(x)=1/cos(x)]
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