Asked by kimberly
solve -[-(-k)]-(-2)(-2+k)=-k-(4k+3)
Answers
Answered by
Reiny
"clean up" all those negative signs first.
-[-(-k)]-(-2)(-2+k)=-k-(4k+3)
-k + 2(-2+k) = -k - 4k - 3
-k - 4 + 2k = -5k - 3
6k = 1
k = 1/6
-[-(-k)]-(-2)(-2+k)=-k-(4k+3)
-k + 2(-2+k) = -k - 4k - 3
-k - 4 + 2k = -5k - 3
6k = 1
k = 1/6
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