Question

A mixture of 10.0g of Ne and 10.0g of Ar was kept in a 1.00 L container at 765 torr. Calculate partial pressure of Ar inside container
A) 508 torr
B) 257 torr
C) 614 torr
D) 125 torr

Answer 1

calculate the moles of each gas.
partial pressure Ne= molesNe/totalmoles * 765torr
partial pressure Ar= molesAr/totalmoles * 765 torr

total moles= moles of each added up. Just looking at the answers, and knowing there are many more moles of Ne than Ar (argon has twice atomic mass as Ne), my guess is 257torr, for Ar pressure. Work it out.