Asked by ATT
Two blocks connected by a cord passing over a small, frictionless pulley rest on
frictionless planes:
a) What is the acceleration of the blocks?
b) What is the tension in the cord?
c) Which way will the system move when the blocks are released from rest? Right or left?
On the left side of the triangle lane is the first block(100kg) at an incline angle of 30degree. On the right side of the triangle plane is the second block (50kg) at an incline of 33.1degree. On top of the triangle plane is the frictionless pulley
frictionless planes:
a) What is the acceleration of the blocks?
b) What is the tension in the cord?
c) Which way will the system move when the blocks are released from rest? Right or left?
On the left side of the triangle lane is the first block(100kg) at an incline angle of 30degree. On the right side of the triangle plane is the second block (50kg) at an incline of 33.1degree. On top of the triangle plane is the frictionless pulley
Answers
Answered by
bobpursley
the force due to gravity down the planes are respectively, 100Sin30; 50sin33.1
forces are + toward the plane with the 100kg block
100sin30-50sin33.3=(150)*acceleration
solve for acceleration.
forces are + toward the plane with the 100kg block
100sin30-50sin33.3=(150)*acceleration
solve for acceleration.
Answered by
ATT
how do I calculate the tesion in the cord? Is it 100sin30 and 50sin33.1?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.