Question

Two blocks connected by a cord passing over a small, frictionless pulley rest on
frictionless planes:
a) What is the acceleration of the blocks?
b) What is the tension in the cord?
c) Which way will the system move when the blocks are released from rest? Right or left?

On the left side of the triangle lane is the first block(100kg) at an incline angle of 30degree. On the right side of the triangle plane is the second block (50kg) at an incline of 33.1degree. On top of the triangle plane is the frictionless pulley
bobpursley
the force due to gravity down the planes are respectively, 100Sin30; 50sin33.1

forces are + toward the plane with the 100kg block
100sin30-50sin33.3=(150)*acceleration
solve for acceleration.
how do I calculate the tesion in the cord? Is it 100sin30 and 50sin33.1?

Related Questions

Two blocks are connected by a cord passing over a small frictionless pulley. The angle is 30 degree... 9. Two blocks connected by a cord passing over a small frictionless pulley rest on frictionless plan... Two blocks connected by a cord passing over a small, frictionless pulley rest on frictionless planes... Two blocks connected by a cord passing over a small, frictionless pulley rest on frictionless planes...