Asked by Greg
Hey I need help factoring 5x^4-180x^2. I'm used to factoring with three numbers, and not two. How would you do just two like this? Thanks
Answers
Answered by
Reiny
first of all I see a common factor of 5x^2
so
5x^4-180x^2
= 5x^2(x^2 - 36)
Now isn't that a difference of squares???
so
5x^4-180x^2
= 5x^2(x^2 - 36)
Now isn't that a difference of squares???
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