Asked by Maben
                The center of a circle is (h, 7) and the radius is 10. The circle passes through (3, -1). Find all possible values of h.
            
            
        Answers
                    Answered by
            scott
            
    (h,7) must lie on a circle of radius 10 , centered at (3,-1)
(x - 3)^2 + (y + 1)^2 = 10^2
(h - 3)^2 + (7 + 1)^2 = 10^2 ... (h - 3)^2 = 100 - 64 = 36
h - 3 = ±6
    
(x - 3)^2 + (y + 1)^2 = 10^2
(h - 3)^2 + (7 + 1)^2 = 10^2 ... (h - 3)^2 = 100 - 64 = 36
h - 3 = ±6
                    Answered by
            Reiny
            
    Scott used the wrong point for the center.
I see it as:
(x-h)^2 + (y-7)^2 = 100
now plug in (3,-1)
(3-h)^2 + (-1-7)^2 = 100
(3-h)^2 = 100 - 64
3-h = ±6
h = 3 ±6
Bonus question: Why did Scott get the same result, even though he had the
incorrect center ?
    
I see it as:
(x-h)^2 + (y-7)^2 = 100
now plug in (3,-1)
(3-h)^2 + (-1-7)^2 = 100
(3-h)^2 = 100 - 64
3-h = ±6
h = 3 ±6
Bonus question: Why did Scott get the same result, even though he had the
incorrect center ?
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