Asked by Muskaan

Assuming the earth to be a uniform sphere of radius 6400 km and density 5.5g/c.c. find the value of g on the surface where G=6.67×10

Answers

Answered by Damon
F = m g = G M m/r^2
actually G = 6.67 * 10^-11
r = 6,400,000 meters = 6.4 * 10^6
rho = 5.5 *10^3 Kg/m^3
M = rho*(4/3) pi r^3 = 23*10^3 r^3


m g = m *6.67*10^-11 *23*10^3 r^3/r^2
g = 6.67*23 *10^-8 (6.4*10^6)
= 983 *10^-2
= 9.83 m/s^2
close enough :)
Answered by bobpursley
if the radius of Earth had been listed as 6378km, it would have been very close.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions