Asked by g

Assuming you are on Earth, where acceleration due to gravity is
9.81 meters/second2, and you have a pendulum with a cord that is 0.65 meters long, what is the period?

Answers

Answered by Henry
T^2 = 4*pi^2*(L/g)
T^2 = 39.48(0.65/9.8). Solve for T.
Answered by Doesn't matter.
Where else am i going to be, !@#$%^&?
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