Asked by g
Assuming you are on Earth, where acceleration due to gravity is
9.81 meters/second2, and you have a pendulum with a cord that is 0.65 meters long, what is the period?
9.81 meters/second2, and you have a pendulum with a cord that is 0.65 meters long, what is the period?
Answers
Answered by
Henry
T^2 = 4*pi^2*(L/g)
T^2 = 39.48(0.65/9.8). Solve for T.
T^2 = 39.48(0.65/9.8). Solve for T.
Answered by
Doesn't matter.
Where else am i going to be, !@#$%^&?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.