Asked by Anonymous
Solve the system of equations.
y=2x^2 -3
y=3x-1
a. no solution
b. (-1/2, 5)(2, -5/2)
c. (-1/2,-5/2) (2,5)***
d. (1/2,5/2) (2,5)
y=2x^2 -3
y=3x-1
a. no solution
b. (-1/2, 5)(2, -5/2)
c. (-1/2,-5/2) (2,5)***
d. (1/2,5/2) (2,5)
Answers
Answered by
MsPi_3.14159265
By substitution or the comparison method set equation 1 equal to equation 2 and solve for x
2x^2-3 = 3x -1 then sub your answer for x back into equation 2 and solve for y : )
2x^2-3 = 3x -1 then sub your answer for x back into equation 2 and solve for y : )
Answered by
Steve
your indicated answer is correct.
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